Guide to Teaching Puzzle-based Learning by Edwin F. Meyer Nickolas Falkner Raja Sooriamurthi & Zbigniew Michalewicz

Author:Edwin F. Meyer, Nickolas Falkner, Raja Sooriamurthi & Zbigniew Michalewicz
Language: eng
Format: epub
Publisher: Springer London, London

(b)Area, where x > y (light part), when the boy is on time

As any point within the rectangle can occur with equal likelihood, it is sufficient to find the ratio between the dark area of the rectangle and the area of the whole rectangle to calculate the probability of the boy being late. This is easy:The dark area: 3 × 3 / 2 = 4.5

The whole rectangle: 4 × 6 = 24

Thus, the probability of the boy being late is exactly

So our earlier estimations, where we used simpler models of the problem, 17 and 18.5 %, were not that bad.

There is also a way for arriving at a solution by simulation. We can generate a large number N of random points A from the intervals 7:58 ≤ x ≤ 8:02 and 7:55 ≤ y ≤ 8:0, with a point A having two coordinates, x and y,

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